May be the charge is when \(x_z\ge a_\psi\).
That the particle is in low oscillation. An example of which is gravity that resonate at \(7.489 Hz\). In this case \(a_\psi\) is in kilometers,
\(f=n\cfrac{c}{2\pi a_\psi}\)
\(7.489=n\cfrac{c}{2\pi a_\psi}\)
\( a_\psi=n\cfrac{c}{2\pi.(7.489)}\), \(c=299792458\)
\( a_\psi=n.6371137\)
when \(n=1\)
\( a_\psi=6371 km\)
which is mind blowing. And Earth is just one big gravity particle.
Merry Christmas!
We experience the force field of these particles when we are in the red zone. Is \(x_z=a_\psi\)? If \(x_z\ne a_\psi\) then as \(\psi\) rotates about, the off center mass regions to the left and right of the mass will overlap. Locations in this region will have two values of \(\psi\) which cannot be the case.
As such, if \(a_\psi\) and \(\psi\) are valid solutions, then,
\(x_z=a_\psi\). And we have,
And we have a big particle for Christmas. Is it possible that \(a_\psi\ge x_z\)? We will not have the overlap issue as in this case, but there will be a gap in the field as shown in the post "Empty On The Inside". \(\psi\) is then a spherical shell around a center.
