Thank You, Al

If time is rotation about the space axis we have the diagram on the left,

If space is rotation about the time dimension we have the diagram on the right.  With the introduction of a third dimension,  $t_{now}$ is represented as,

Note: The rest of the post is wrong.  $t_{now}$ is not rotated in the $t_{now}$-$t_{c}$ plane.  Instead its projection onto the $t_T$-$t_c$ plane is rotated $60^o$. Please refer to the later post "Rotating Al Again".  The change in phase to achieve invisibility is such that after the rotation the $t_c$ component of the rotated $t_{now}$ is orthogonal to the old $t_c$ axis, which is the $t_c$ axis of an outside observer.  However, the phase change needed to achieve optical invisibility is consistent with the introduction of a third time dimension $t_T$.

And angle $\theta$ is given by,

$\theta=arcsin(\sqrt{\cfrac{2}{3}})=54.74^o$

and the angle to the vertical in the plane containing $t_{now}$ and $t_c$ is,

Time Bias $\measuredangle = 90^o-54.74^o=35.26^o$

This explains the time bias highlighted in the post "Time Bias", concerning "The Philadelphia Experiment".  where a phase of $60^o$ was enough to cause optical invisibility not $90^o$.

The small discrepancies $60^o-54.74^o=5.26^o$ is due to low signal and noise.  Our eyes and equipment cannot detect optical signals that are too low.  Practical optical invisibility occurs $5.26^o$ before $t_{rotated}$ is orthogonal to $t_{now}$.

The Philadelphia Experiment provided evidence in support for a third time dimension.