If space is rotation about the time dimension we have the diagram on the right. With the introduction of a third dimension, \(t_{now}\) is represented as,
Note: The rest of the post is wrong. \(t_{now}\) is not rotated in the \(t_{now}\)-\(t_{c}\) plane. Instead its projection onto the \(t_T\)-\(t_c\) plane is rotated \(60^o\). Please refer to the later post "Rotating Al Again". The change in phase to achieve invisibility is such that after the rotation the \(t_c\) component of the rotated \(t_{now}\) is orthogonal to the old \(t_c\) axis, which is the \(t_c\) axis of an outside observer. However, the phase change needed to achieve optical invisibility is consistent with the introduction of a third time dimension \(t_T\).
And angle \(\theta\) is given by,
\(\theta=arcsin(\sqrt{\cfrac{2}{3}})=54.74^o\)
and the angle to the vertical in the plane containing \(t_{now}\) and \(t_c\) is,
Time Bias \(\measuredangle = 90^o-54.74^o=35.26^o\)
This explains the time bias highlighted in the post "Time Bias", concerning "The Philadelphia Experiment". where a phase of \(60^o\) was enough to cause optical invisibility not \(90^o\).
The small discrepancies \(60^o-54.74^o=5.26^o\) is due to low signal and noise. Our eyes and equipment cannot detect optical signals that are too low. Practical optical invisibility occurs \(5.26^o\) before \(t_{rotated}\) is orthogonal to \(t_{now}\).
The Philadelphia Experiment provided evidence in support for a third time dimension.
