Friday, December 19, 2014

Where Inertia Is Charge

From the post "One Plus One Plus One",

\(q_\rho=\sqrt { 2{ mc^{ 2 } } }\,G\)

If \(q\) is consider inertia along the \(t_c\) time axis, such that

\(q=Aq_\rho\)

\(q_{ \rho  }=\cfrac { 1 }{ 2Ac^{ 2 }G^{ 2 } }\)

\(q_{ \rho  }=\cfrac { 1 }{ 2\pi c^{ 2 }a^{ 2}G^{ 2 } }\)

where \(a\) is the radius of the disc that defines \(q\).  And \(q_\rho=0\) is a valid solution too.