| n | \(f\) | \(\lambda\) (nm) |
|---|---|---|
| 0 | 0 | - |
| 1 | 2466067.5 | 121.56701 |
| 1 | 2922728.6 | 102.5728 |
| 1 | 3082568.8 | 97.2541 |
Three regression lines are plotted below,
Basically,
\(f=n\cfrac{c}{2\pi a_\psi}\), \(n=1\)
From this we obtained three values for \(a_\psi\)
\(\cfrac{c}{2\pi a_\psi}=2466067.5\)
\(a_\psi=19.34\) nm
\(\cfrac{c}{2\pi a_\psi}=2922728.6\)
\(a_\psi=16.32\) nm
\(a_\psi=15.48\) nm
and from the previous post where \(\psi\) oscillates in two space dimensions, and is most restricted,
\(a_\psi=14.77\) nm
These values are the extend of \(\psi\) around the particles in space, they are not the radius of the underlying mass. In the case of photons there are no mass under \(\psi\), all the energy of the particle is manifested as \(\psi\).
A greater resistance to \(\psi\) in the time dimension results in a greater extend of \(\psi\) in the space dimension, \(a_\psi\) is higher for such photons. Nonetheless, time dimensions as a whole presents less resistance to \(\psi\) than the space dimensions, so much so that all energy of a photon oscillating between one space and one time dimension is fully manifested as \(\psi\).
Photons with greater extend of \(\psi\) in space, ie larger \(a_\psi\), oscillates at lower frequencies.
Can I get the momentum of photon from here?
