In the case of an electron,
h=2πaψemec
aψe=h2π1mec
aψe=ℏ1mec=(1.054571726e−34)/(9.10938291e−31∗299792458)
aψe=3.862e−13 m
And aψe can be obtained numerically. This is a small value for one electron. This does not explain the repulsion of two negatively charged conductors.
Nor does this value match any of the four values obtained previously of basic particles. The assumption of n=1 could be wrong in those calculations.
More importantly, beyond aψ an electron exert a small positive repulsive force.
In the case when xz=aψ then the extend of ψ around the electron mass is,
rψe=2aψ=7.724e−13 m
where rψe is the radius of a sphere around me.
But me itself is a flat disc. Should ψ also be a flat disc?? If me is at the center of ψ then,
rψe=aψ=3.862e−13 m
And so, rψe is between 3.862e−13 to 7.724e−13 m.