we find that \(F\) due to \(F_\rho\) is always positive. As the next graph shows, the individual \(\psi_{+1}\) and \(\psi_{-1}\) disappeared and the particle is fully manifested as mass.
But
\(m_{ \rho \, p }c^{ 2 }=m_{ \rho }c^{ 2 }-\int _{ 0 }^{ 2x_{ z} }{ \psi_{+1} } dx\)
\(m_{ \rho \, p }c^{ 2 }=m_{ \rho }c^{ 2 }-\int _{ 0 }^{ 2x_{ z} }{ \psi_{-1} } dx\)
\(\psi=\psi_{+1}+\psi_{-1}\)
And the total mass of the system, \(m_{ \rho \, s }\) is,
\(m_{ \rho \, s }=2m_{ \rho }\)
This is a proton. Positively charged and has mass \(2m_\rho\).
Which would explain why some materials get positively charged. \(\psi\) alone \(F\) can be negative, two \(\psi\)s in sum, their resultant \(F\) is positive. Two particles in orbit result in a \(\psi\) distribution that exert a positive force \(F\) (Newtonian) around it. (Note: Pairing of electrons in electronic configuration of elements.)
However if this pair were to oscillates at \(a_\psi\),
And a pair of negative charges summed to turn positive and then turn negative when oscillating at \(a_\psi\), if they oscillate as a group. Absurdity!
