Positively Charged Absurdity

If we add two $\psi$s separated by a distance,

we find that $F$ due to $F_\rho$ is always positive.  As the next graph shows, the individual $\psi_{+1}$ and $\psi_{-1}$ disappeared and the particle is fully manifested as mass.

But

$m_{ \rho \, p }c^{ 2 }=m_{ \rho  }c^{ 2 }-\int _{ 0 }^{ 2x_{ z} }{ \psi_{+1}  } dx$

$m_{ \rho \, p }c^{ 2 }=m_{ \rho  }c^{ 2 }-\int _{ 0 }^{ 2x_{ z} }{ \psi_{-1}  } dx$

$\psi=\psi_{+1}+\psi_{-1}$

$2m_{ \rho \, p }c^{ 2 }=2m_{ \rho  }c^{ 2 }-\int _{ 0 }^{ 2x_{ z} }{ \psi  } dx$

And the total mass of the system, $m_{ \rho \, s }$ is,

$m_{ \rho \, s }=2m_{ \rho  }$

This is a proton.  Positively charged and has mass $2m_\rho$.

Which would explain why some materials get positively charged.  $\psi$ alone $F$ can be negative, two $\psi$s in sum, their resultant $F$ is positive.  Two particles in orbit result in a $\psi$ distribution that exert a positive force $F$ (Newtonian) around it.  (Note:  Pairing of electrons in electronic configuration of elements.)

However if this pair were to oscillates at $a_\psi$,

And a pair of negative charges summed to turn positive and then turn negative when oscillating at $a_\psi$, if they oscillate as a group. Absurdity!