\(T_\rho=\sqrt { 2{ mc^{ 2 } } }\,G\)
where \(T\) is considered inertia along the \(t_T\) time axis, such that
\(T=AT_\rho\)
\(T_{ \rho }=\cfrac { 1 }{ 2Ac^{ 2 }G^{ 2 } }\)
\(T_{ \rho }=\cfrac { 1 }{ 2\pi c^{ 2 }a^{ 2}G^{ 2 } }\)
\(a\) is the radius of the disc that defines \(T\). And \(T_\rho=0\) is a valid solution too.
The two types of temperature particles are shown above.
