With ZnTiO3, with Zm=30+22+8∗3=76, molar mass of 161.24gmol−1 and a density of 5.18gcm−3,
vboom=3.4354∗518076=234.14ms−1
and
Tboom=234.142∗161.24∗10−33∗8.3144=354.41K or 81.26oC
If ZnTiO3 crystal are reduced in density to 91.72% by adding a dopant (Mn, Fe are all capable of oxidation state +3), then Tboom is reduced by,
Tboom=0.91722∗354.41=298.15K or 25.00oC
Changing the crystal's density tunes down Tboom. Goodnight.