Tuning Down $T_{boom}$

With $ZnTiO_3$, with $Z_m=30+22+8*3=76$, molar mass of $161.24\,gmol^{-1}$ and a density of $5.18\,gcm^{-3}$,

$v_{boom}=3.4354*\cfrac{5180}{76}=234.14\,ms^{-1}$

and

$T_{boom}=234.14^2*\cfrac{161.24*10^{-3}}{3*8.3144}=354.41\,K$ or  $81.26\,^oC$

If $ZnTiO_3$ crystal are reduced in density to 91.72% by adding a dopant ($Mn$, $Fe$ are all capable of oxidation state $+3$),  then $T_{boom}$ is reduced by,

$T_{boom}=0.9172^2*354.41=298.15\,K$ or  $25.00\,^oC$

Changing the crystal's density tunes down $T_{boom}$.  Goodnight.