\(A_{\small{D}}=\cfrac{4}{3}\pi(2c)^3\)
and
\(R=2*\cfrac{4}{3}\pi=8.377580\)
From the Kinetic Theory of ideal gas,
\(v^2_{rms}=\cfrac{3RT}{M_m}\)
\(v^2_{rms}=\cfrac{3*2*\cfrac{4}{3}\pi T}{m_a\cfrac{4}{3}\pi(2c)^3}\)
where \(m_a\) is the mass of one gas particle. We have,
\(\cfrac{1}{2}m_av^2_{rms}=\cfrac{3T}{(2c)^3}\)
\(T=\cfrac{(2c)^3}{3}*\cfrac{1}{2}m_av^2_{rms}\)
The factor \(\cfrac{1}{3}\) accounts for any one direction of travel of the particle in a \(3D\) volume and \((2c)^3\) is the volume containing all the particles numbered in one Durian Constant, within which they are all entangled.
This does not validate \(T_{boom}\), but shows in general what \(T\) here measures as oppose to the number of \(T^{+}\) or \(T^{-}\) particles. \(T\) indicates the total kinetic energy of all the particles within a \((2c)^3\) volume, along one particular direction.
If \(m_a\) is in mass density then, the term
\((2c)^3\)*m_a
is the total mass within the volume. With the factor \(\cfrac{1}{3}\) we are concern only with one of the three orthogonal directions in space.
Have a nice day.
