A table of water density and \(T_{boom}\) at various temperature is shown below
| Temp oC | H2O Density kg/m3 | v boom (m/s) | T boom (K) |
| 100 | 958.40 | 329.25 | 78.30 |
| 80 | 971.80 | 333.85 | 80.50 |
| 60 | 983.20 | 337.77 | 82.40 |
| 40 | 992.20 | 340.86 | 83.92 |
| 30 | 995.65 | 342.05 | 84.50 |
| 25 | 997.05 | 342.53 | 84.74 |
| 22 | 997.77 | 342.78 | 84.86 |
| 20 | 998.21 | 342.92 | 84.93 |
| 15 | 999.10 | 343.23 | 85.09 |
| 10 | 999.70 | 343.44 | 85.19 |
| 4 | 999.97 | 343.53 | 85.24 |
| 0 | 999.84 | 343.48 | 85.21 |
| −10 | 998.12 | 342.89 | 84.92 |
| −20 | 993.55 | 341.32 | 84.14 |
| −30 | 983.85 | 337.99 | 82.51 |
Maximum \(T_{boom}=85.24\,K\) is at \(4\,^oC\) at a density of \(999.97\,kgm^{-3}\).
What to do next? \(n\) also changes with temperature...We calculate \(n\) using
\(n=\cfrac{Temp+273.15}{T_{boom}}\)
| Temp ( C) | T boom (K) | n |
| 100 | 78.30 | 4.77 |
| 80 | 80.50 | 4.39 |
| 60 | 82.40 | 4.04 |
| 40 | 83.92 | 3.73 |
| 30 | 84.50 | 3.59 |
| 25 | 84.74 | 3.52 |
| 22 | 84.86 | 3.48 |
| 20 | 84.93 | 3.45 |
| 15 | 85.09 | 3.39 |
| 10 | 85.19 | 3.32 |
| 4 | 85.24 | 3.25 |
| 0 | 85.21 | 3.21 |
| -10 | 84.92 | 3.10 |
| -20 | 84.14 | 3.01 |
| -30 | 82.51 | 2.95 |
that give the size of the water molecule cluster that would elevate \(T_{boom}\). Such clustering increases the effective molar mass of the particles in motion that in turn requires a higher temperature to achieve a given \(v_{rms}=v_{boom}\) speed.
Do the data make sense?
No it does not. Water has 3.4 hydrogen bonds and ice has 4, and so, we expect clusters of 4.4 and 5, respectively.
This treatment of the data is asserting that, not only are melting and boiling nuclear, but temperature itself is due to \(T_{boom}\).
And winner takes all...
