\(v_{boom}=3.4354*\cfrac{7874}{26}=1040.40\,ms^{-1}\)
\(T_{boom\,p}=\cfrac{1040.40^2*0.055845}{2*8.3144}=3635.16\,K\) or \(3362.01\,^oC\)
Iron has a melting point of \(1811\,K\) and a boiling point of \(3134 K\)
And the most nuclear \(T_{boom\,p}\) bring iron beyond its boiling point.