Plasma Reactor And A Hot Fan

The previously EMP device using an ornamental $H_2$ discharge globe,

with the correct rotational velocities we have plasma.  Given that temperature is directly proportional to mean square speed of the free molecules inside a containment, at the correct temperature $T_{v\,boom}$, the molecules disintegrate into $\psi$ particles.

In the case of carbon with a density of $d=2267\,kgm^{-3}$,

$v_{boom\,C}=3.4354*\cfrac{2267}{6}=1298.0\,ms^{-1}$

If at temperature $T_{1298}$ the carbon atom has a average vibration speed of  $v_{boom\,C}$ and we seal carbon (coal) in a fortified containment at this temperature,

we may have a sustained reactor producing heat.  If we operate at a temperature of $T_{1298}+\Delta T$ where a drop in temperature, $\Delta T$ prompts the system to produce more heat at $T_{1298}$, then energy can be tapped off the reactor.

If we assume that $C$ atoms are free to move at temperature around $T_{1298}$,

$v_{boom}=v_{rms}=\sqrt{\cfrac{3RT_{v\,boom}}{M_m}}$

where $R$ is the gas constant, $M_m$ is the molar mass, and $v_{rms}$ the root mean square speed.  In the case of carbon $^{12}C$,

$T_{1298}=\cfrac{1298^2*12.0107*10^{-3}}{3*8.3144}=811.3\,K$

obviously the assumption cannot hold! This temperature is way low for $C$ to be in a gaseous state.  The formula for $v_{rms}$ cannot be used here, maybe.  Nonetheless, if we heat a sealed containment of coal to around $538.27^oC$ do we have a sustained heat source?

In general, given temperature $T=T_{v\,boom}$ in a sealed containment without the danger of combustion, we can have a sustained plasma reactor producing heat.

In the case of atmospheric $N_2$ where the density has been reduced by a factor of  $0.7809$.

$v_{boom\,air}=0.286*0.7809=0.2233\,ms^{-1}$

If you have a fan turning at this speed, the wind coming from the blade will feel hot because of $v_{boom}$ of air.  And the fan keeps warmth.

Good night.

Note: The real technology is to reduce density such that $v_{boom}$ or $v^2_{boom}$ produces a manageable $T_{v\,boom}$ temperature.  $v^2_{boom}$ is used in,

$v_{boom}=v_{rms}=\sqrt{\cfrac{3RT_{v\,boom}}{M_m}}$

from the kinetic theory of gases using Maxwell–Boltzmann distribution.

In the cases of gases, set the globe rotating at $v_{boom}$ and measure the stabilized temperature.