with the correct rotational velocities we have plasma. Given that temperature is directly proportional to mean square speed of the free molecules inside a containment, at the correct temperature \(T_{v\,boom}\), the molecules disintegrate into \(\psi\) particles.
In the case of carbon with a density of \(d=2267\,kgm^{-3}\),
\(v_{boom\,C}=3.4354*\cfrac{2267}{6}=1298.0\,ms^{-1}\)
If at temperature \(T_{1298}\) the carbon atom has a average vibration speed of \(v_{boom\,C}\) and we seal carbon (coal) in a fortified containment at this temperature,
we may have a sustained reactor producing heat. If we operate at a temperature of \(T_{1298}+\Delta T\) where a drop in temperature, \(\Delta T\) prompts the system to produce more heat at \(T_{1298}\), then energy can be tapped off the reactor.
If we assume that \(C\) atoms are free to move at temperature around \(T_{1298}\),
\(v_{boom}=v_{rms}=\sqrt{\cfrac{3RT_{v\,boom}}{M_m}}\)
where \(R\) is the gas constant, \(M_m\) is the molar mass, and \(v_{rms}\) the root mean square speed. In the case of carbon \(^{12}C\),
\(T_{1298}=\cfrac{1298^2*12.0107*10^{-3}}{3*8.3144}=811.3\,K\)
obviously the assumption cannot hold! This temperature is way low for \(C\) to be in a gaseous state. The formula for \(v_{rms}\) cannot be used here, maybe. Nonetheless, if we heat a sealed containment of coal to around \(538.27^oC\) do we have a sustained heat source?
obviously the assumption cannot hold! This temperature is way low for \(C\) to be in a gaseous state. The formula for \(v_{rms}\) cannot be used here, maybe. Nonetheless, if we heat a sealed containment of coal to around \(538.27^oC\) do we have a sustained heat source?
In the case of atmospheric \(N_2\) where the density has been reduced by a factor of \(0.7809\).
\(v_{boom\,air}=0.286*0.7809=0.2233\,ms^{-1}\)
If you have a fan turning at this speed, the wind coming from the blade will feel hot because of \(v_{boom}\) of air. And the fan keeps warmth.
Good night.
Note: The real technology is to reduce density such that \(v_{boom}\) or \(v^2_{boom}\) produces a manageable \(T_{v\,boom}\) temperature. \(v^2_{boom}\) is used in,
\(v_{boom}=v_{rms}=\sqrt{\cfrac{3RT_{v\,boom}}{M_m}}\)
from the kinetic theory of gases using Maxwell–Boltzmann distribution.
In the cases of gases, set the globe rotating at \(v_{boom}\) and measure the stabilized temperature.
