To admit basic particles that are free in a solids, we have to look at the expression,
\(v_{boom}=3.4354*\cfrac{density}{particle\,count\,per\,type}\)
again.
\(Z=1\) for basic particles.
In case of basic particles alone,
\(v_{boom\,particles}=3.4354*{density}\) - (1)
where \(density\) is the particle density within the confined volume in a solid or a gas containment.
In the case of basic particles colliding with the lattice cells,
\(v_{boom}=3.4354*\cfrac{density}{(Z=1)*(particle\,count\,per\,type)}\) -- (2)
which the same as before.
In the case of a gas,
\(v_{boom}=3.4354*\cfrac{density}{(particle\,count\,per\,type)*(particle\,count\,per\,type)}\) --- (3)
where molecules collide. Particle count per type is the total number of particles of one type that constitute the molecule.
In a solid and liquid we have the superposition of (1) and (2). In a gas we have the superposition of (1), (2) and (3). We might add, in the case of basic particles colliding with matter in the liquid state,
\(v_{boom}=3.4354*\cfrac{density}{(Z=1)*m*(particle\,count\,per\,type)}\) -- (4)
where \(m\) is the average number of molecules in a cluster/chain in the liquid state.
If these other scenario occurs, then the plot of energy states given temperature will be the superposition of two or more graphs as enumerated above. Each change in phase (solid\(\rightarrow \)liquid, liquid\(\rightarrow \)gas) introduces a new superimposed graph.
As an after thought, we might also add, collisions between molecule clusters in a gas,
\(v_{boom}=3.4354*\cfrac{density}{m*(particle\,count\,per\,type)*m*(particle\,count\,per\,type)}\) --- (5)
where \(m\) is the average molecular cluster size in the gas. And
\(v_{boom}=3.4354*\cfrac{density}{m*(particle\,count\,per\,type)*(particle\,count\,per\,type)}\) --- (6)
for collisions between molecule clusters and singular molecule in a gas
And things get complicated, with many shadows.
