vboom=3.4354∗602056+22+8∗3=202.76ms−1
Tboom=202.762∗233.192∗10−32∗8.3144=576.50K or 303.35oC
This is way hot. Temperature is know to decrease conductivity. An impossible hot superconductor.
For CaCu3Ti4O12,
vboom=3.4354∗470020+29∗3+22∗4+8∗12=55.49ms−1
Tboom=55.492∗614.1789∗10−32∗8.3144=43.17K or −229.98oC
This is cold. The cell unit is too big to be considered as a quasi-nucleus. Maybe it is possible to parcel out molar mass and arrive at a density value for copper only in the crystal structure.
fCu=totalmolarmassCutotalatomicmolarmass
MmCu=Mm∗fCu≈molarmassCu
where Mm is molecular mass,
ρcu=ρm.fcu
where ρm and ρcu are crystal density and density of Cu in the structure, and so consider only copper in the structure.
So,
fCu=63.546∗3614.1789=0.310
ρcu=4700∗0.310=1458.86kgm−3
Considering only Cu in CaCu3Ti4O12,
vboom=3.4354∗1458.8629∗3=57.60ms−1
Tboom=57.602∗63.546∗3∗10−32∗8.3144=38.03K
It does not seem to work. Furthermore, to consider collisions with Cu only, the atomic will have to dominate the structure in size. The rest of the molecules is as if does not exist. Even so, three separate Cu atoms does not form a quasi-nucleus. Maybe,
vboom=3.4354∗1458.8629=172.82ms−1
Tboom=172.822∗63.546∗10−32∗8.3144=114.13K
What about copper by itself as a metal;
vboom=3.4354∗896029=1061.42ms−1
Tboom=1061.422∗63.546∗10−32∗8.3144=4305.29K or 4032.14oC
which is not indicative of its high conductivity of electricity. For this reason a folly...
