Iron Melted At $T_{boom}$

Please be reminded of $E=mc^2$.  Small amount of mass is equivalent to huge amount of energy.

For Iron $Fe$, $Z=26$, molar mass of $0.055845\,kgmol^{-1}$, density of $7874\,kgm^{-3}$

$v_{rms}=3.4354*\cfrac{7874}{26}=1040.40\,ms^{-1}$

$T_{boom}=\cfrac{1040.40^2*0.055845}{3*8.3144}=2423.44\,K$  or $2150.29\,^oC$

Iron has a melting point of  $1811\,K$ and a boiling point of $3134 K$

What happens to iron at $2423.44\,K$?  Red Hot?  No, red hot in all shades are below the melting point.

The density of iron at $2150.29\,^oC$ is expected to be different from $7874\,kgm^{-3}$.  So, what happens to iron around $2150.29\,^oC$?  If at this temperature iron is completely sealed off from oxidizing does it remain at $T_{boom}$?