Sodium, \(Na\) \(density=9680\,kgm^{-3}\) \(M_m=22.9898\,g/mol\) and \(Z=11\),
\(v_{boom}=3.4354*\cfrac{9680}{26}=1279.0\,ms^{-1}\)
\(T_{boom}=1279.0^2*\cfrac{22.9898*10^{-3}}{3*8.3144}=1507.73\,K\)
The boiling point of sodium being \(1156.090\,K\)
At its melting point (\(370.944\,K\)) its density is \(9270\,kgm^{-3}\)
\(v_{boom}=3.4354*\cfrac{9270}{26}=1224.9\,ms^{-1}\)
\(T_{boom}=1224.9^2*\cfrac{22.9898*10^{-3}}{3*8.3144}=1382.77\,K\)
Maybe there can be a \(Na\) bomb, when it is completely vaporize at \(1507.73\,K\) exactly (very high yield!), but its density remains at \(9680\,kgm^{-3}\) because it is sealed completely ie, volume does not change and mass within the containment does not change.
Temperature is not \(T_{boom}\) as density changes with temperature, because density decreases with temperature and so does \(T_{boom}\).
Does \(T_{boom}\) indicate that a substance can be use as a fuel?
