New Take On $T_{boom}$

If $T_{boom}$ is temperature, then given a sealed containment of a fixed density, (volume does not change, mass decrease very slowly), $v_{boom}$ is fixed and so is $T_{boom}$

$v_{boom}=3.4354*\cfrac{density}{Z}$

Density fixed, $v_{boom}$ fixed.

$T_{v\,boom}=\left(\cfrac{3.4354*density}{no.\,of\,particles}\right)^2*\cfrac{molar\,mass*10^{-3}}{3*8.3144}$

Density fixed, $T_{boom}$ fixed.

For any sealed reactor, a particular $T_{boom}$ given the density of the material in the reactor.

At $T_{boom}$, the reactor releases huge amount of energy that resist any drop in temperature.  The reactor remains at $T_{boom}$.  It is still possible to over-drain the reactor and drive it below $T_{boom}$.  Below $T_{boom}$ temperature decreases.

In other words, fill up the sealed reactor full!