In the post "One Plus One Plus One" dated 18 Dec 2014,
ψ, F and q all adds up. At the plateau, for Z number of particles,
ln(cosh(G√2mc2xz))→Z∗ln(cosh(G√2mc2xz))=Z
So,
ψn→Z∗ψn
and under the strict condition,
ψdm=2c2cos(θ)ln(cosh(G√2mc2xz))
from the post "Twirl Plus SHM, Spinning Coin" dated 17 Jul 2015, ψd is the displacement of ψ in the containing ψ cloud that performs SHM. So,
ψdm→Z∗ψdm
but ψmax is still one particle, n=77 (as defined),
ψmax=1
with mormρ=12c2∗12.4438
so,
v2max=−Z∗ψdmZ∗ψnψmax eψmax(e2ψmax−1)1/2
thus,
v2max→Z2∗v2max
Note: I have a few missing posts on the new mode of oscillations; of SHM within ψ.
ψd=ψmax−ψn --- (*)
is only for a particle of ψmax receiving a particle of ψn, as the scenario is developed in the post "Twirl Plus SHM, Spinning Coin" dated 17 Jul 2015. ψd is the displaced ψ in SHM in general and is not restricted to (*).
Note: If ψmax is also scaled then all the particles in the expression for vmax is scaled by Z which lead back to the situation without scaling.