\(v^{ 2 }_{ { max } }=\cfrac { 1 }{ m } \cfrac { \psi _{ n } }{ \psi _{ max } }\left\{ \psi _{ n }-\psi _{ max } \right\} e^{ \psi _{ max } }\left( { e^{ 2\psi _{ max } }-1 } \right) ^{ 1/2 }\)
\(v^{ 2 }_{ { max } }\lt0\)
\(v_{ { max } }=i\sqrt{\left|\cfrac { 1 }{ m } \cfrac { \psi _{ n } }{ \psi _{ max } }\left\{ \psi _{ n }-\psi _{ max } \right\} e^{ \psi _{ max } }\left( { e^{ 2\psi _{ max } }-1 } \right) ^{ 1/2 }\right|}\)
from the post "Peanuts And Peanut Butter" dated 09 Dec 2017, is a torus shaped particle.
Does it remain a torus of total \(\psi=\psi_n\) or does it expand continuously and disperse into a mist of \(\psi\). Does the torus collapse into a spherical particle?
If this entity disperses into a mist then, all particles in this mist tend to positive charge as the mist coalesce with the particles, and all bigger particles are positive (except neutral at \(a_{\psi\,ne}\)).
If this particle collapses into a spherical particle, it will be with the absorption of energy, as \(\psi\) then goes around a smaller radius \(a_{\psi}\), at a higher frequency.
Both positive and negative fields are present around the torus and the field lines wrap around the particle through the hole in the middle.
This could be the smallest magnetic particle with both poles, or an electric dipole or a gravity dipole.
When the torus collapses, only one particle is left. The single particle can be positive or negative depending on its size. This is not a dipole formed from two opposite charges.
The absorption line from this entity when it collapses will not fit any of the absorption series. The formation of this torus may result in a separate emission of energy, in which case, the absorption line will not be seen. If the torus is ejected with less energy absorbed than when a spherical particle is ejected, ie. without a separate emission of energy, then the absorption line as the torus collapses can be seen. Also, the lower energy absorption line due to the impact that created the torus, can also be seen.
How big does the torus get?
Good night.
Note; What happen to the impact particle? The theory goes up to the point of impact in time, when \(\psi_n\) is ejected, \(\psi_d=\psi_n-\psi_{max}\) is oscillating in the big particle. What happens to the impact particle afterwards? Never say. Unknown.
It could coalesce with the big particle and the process emits a photon.
