Amnesia's Dream: Temperature Potential

Wednesday, December 27, 2017

What is,

T_{k} = r * \frac{T}{T_{g}}

$T_k=r*\cfrac{T}{T_g}$

r = \frac{q_{g}}{ε_{g} k Δ T}

$r=\cfrac{q_g}{\varepsilon_gk\Delta T}$

or

Δ T = T - T_{g} = \frac{q_{g}}{ε_{g} k * r}

$\Delta T=T-T_g=\cfrac{q_g}{\varepsilon_gk*r}$

using

V_{m}

$V_m$ , from the post "Otherwise An Idiot..." dated 28 Dec 2017. Does it make sense?

T_{g} = \frac{ρ_{c}}{ε_{c}} \neq \frac{ρ_{g, P \to \infty}}{ε_{g}}

$T_g=\cfrac{\rho_c}{\varepsilon_c}\ne\cfrac{\rho_{\small{g,\,P\rightarrow \infty}}}{\varepsilon_g}$

only for

P \to \infty

$P\rightarrow \infty$ is

\frac{ρ_{c}}{ε_{c}} = \frac{ρ_{g, P \to \infty}}{ε_{g}}

$\cfrac{\rho_c}{\varepsilon_c}=\cfrac{\rho_{\small{g,\,P\rightarrow \infty}}}{\varepsilon_g}$

Or should we consider instead,

T_{k} = r_{g} * \frac{T}{Δ T}

$T_k=r_g*\cfrac{T}{\Delta T}$

r_{g} = \frac{q_{g}}{ε_{g} k T_{g}}

$r_g=\cfrac{q_g}{\varepsilon_gk T_g}$

What is

T_{g} = \frac{q_{g}}{ε_{g} k * r_{g}}

$T_g=\cfrac{q_g}{\varepsilon_gk *r_g}$

??

Have a nice day?

Wednesday, December 27, 2017