Only If You Started Somewhere

From the post "Match Making Kinetic Theory And Temperature Particles" dated 27 Dec 2017:

It should be,

$kT_g=\cfrac{q_g}{\varepsilon_g *r_g}$

where $kT_g$ is in Joules per particle, and $\cfrac{q_g}{\varepsilon_g *r_g}$ is potential ($J$) due to temperature charges on one particle.

Only if one started somewhere somehow, anywhere anyhow...

$T_k=r*\cfrac{T}{T_g}$

where  $r=\cfrac{q_g}{\varepsilon_g k\Delta T}$ or

$T_k=r_g*\cfrac{T}{\Delta T}$

where  $r_g=\cfrac{q_g}{\varepsilon_g kT_g}$

(T_k\) is made up of $\cfrac{T}{\Delta T}$ up to the length $r_g$ of a field projected by the total temperature charge per particle, up to a potential of $V=kT_g$.  Where $T_g$ is the temperature of the gas when the temperature particles it contains, fill the gas evenly at a volume of $V_m$, radius $r=3$.  $T$ is the measured temperature at the surface, and $\Delta T$ is the difference between the measured temperature $T$ and $T_g$.

If the temperature charge particles are free from the gas particles, $T=T_g$ where the measured temperature is the same as the temperature of the gas just below the inner surface of the containment.  $T$ is independent of $T_k$.

If the temperature charge particles are bounded to the gas particles and moves to the interior of the gas as the gas particles moves, then $T\ne T_g$ and $T_k$ is related as above.

At high temperature and high pressure it is likely that $T$ is independent of $T_k$ as more temperature particles are free from the gas particle.  $T_g$ then measures the temperature charge content of the gas, as in the case of a conductor imbued with electric charges.

$T_g\equiv\cfrac{\rho_{e\,area}}{\varepsilon}=D$

Have a nice day.