where \(a_{\psi}=16.32\,nm\) is the value of \(a_{\psi\,ne}\).
But if,
\((n_2=2n_e)\rightarrow (n_1=n_e)+n_e\)
gives one photon \(a_{\psi\,ne}\), then
\((n_3=3n_e)\rightarrow (n_2=2n_e)+n_e\)
also gives one photon \(a_{\psi\,ne}\). And both,
\((n_4=4n_e)\rightarrow (n_2=2n_e)+2n_e\)
\((n_2=3n_e)\rightarrow (n_1=2n_e)+n_e\)
give photon \(a_{\psi\,2ne}\).
What if they are all photons liberated, and we have,
where the smallest photon \(a_{\psi\,ne}\) has the highest energy.
\(a_{\psi}\) remains undetermined...
