What happens when we jiggle this transformed particle in the time dimension at,
\(f=280.73\,Hz\)
???
I don't know...
Maybe to be consistent, we consider a volume of size,
\(Vol_{time}=\cfrac{4}{3}\pi T^3=\cfrac{4}{3}\pi* \cfrac{1}{f^3}\)
instead. In which case,
\(P=\cfrac{8^3}{18}\pi^2*f^2*m_ac^2=1*\cfrac{3}{4\pi}*f^3*m_ac^2\)
\(f=\cfrac{4*8^3}{3*18}\pi^3=1175.942\,Hz\)
a low hum...
And we shall keep the factor \(\cfrac{4}{3}\pi=4.1888\) in mind.
\(f=f=\cfrac{4*8^3}{3*18}\pi^3\)
Maybe this is part of the reason we needed \(\mu_o=4\pi\times10^{-7}\). The factor \(\cfrac{1}{3}\) can be removed by considering \(3R\) in place of \(R\) in the post "What If The Particles Are Photons?" dated 12 Dec 2017, as we move from one direction to all 3D space in a volume containing \(P\).
Have a nice day.
