aψπaψc=cosh−1(e)cosh−1(e1/4)
aψπaψc=2.24921
From the post "Deep Blue Deeper" dated 01 Jun 2016,
dqdx|aψ=3k−2∂T∂x|aψ
where,
∂ψ∂x=∂V∂x+∂T∂x=k
a constant and, x≤aψπ.
and the post "Why A Positron And Deep Blue..." dated 01 Jun 2016,
dqdx=[3∂V∂x+∂T∂x]x=aψ
But we know that aψc is at a higher frequency than aψπ. And intuitively,
∂T∂x|aψπ<∂T∂x|aψc
∵aψc<aψπ and both particles are waves wrap around a center at light speed.
If ∂T∂x∝1aψ, as in the case of gravitational force under earth's surface (a force being the rate of change of energy with distance), that,
∂T∂x|aψc=aψπaψc∂T∂x|aψπ
∂T∂x|aψc=2.24912∂T∂x|aψπ
So,
dqdx|aψc=3k−2∂T∂x|aψc
dqdx|aψc=3k−2∗2.24912∂T∂x|aψπ
dqdx|aψc=3∂V∂x|aψπ−1.49824∂T∂x|aψπ
where ∂ψ∂x|aψπ=∂V∂x|aψπ+∂T∂x|aψπ=k
since,
∂ψ∂x=∂V∂x+∂T∂x=k
is true for values of x≤aψπ. So,
dqdx|aψc=[3∂V∂x−1.49824∂T∂x]x=aψπ
but,
dqdx|aψπ=[3∂V∂x+∂T∂x]x=aψπ
dqdx is also a force; from the two expressions, the resultant interaction of aψc and aψπ is attractive, as the common component in the two sums,
3∂V∂x
cancels and the leading coefficients of the term
∂T∂x
sums to a negative value (−0.49824) and results in a decrease in T (kinetic energy KE) along x.
In the case when aψπ interacts with aψπ both particle experience positive change in kinetic energy in the direction of x and they move further apart. The potential component still cancels, as both particles change PE in the opposite directions. The interaction of two aψc particles however, is still attractive due to the negative coefficient to the KE term,
∂T∂x
So, aψc particles will coalesce to size n=ne, where
aψπaψne=ratioe
until the substitution into the expression,
dqdx|aψc=3k−2∂T∂x|aψc
does not result in a negative coefficient to the term,
∂T∂x
ie,
2∗ratioe<3
ratioe<1.5
or
aψπaψne<1.5
Only after attaining the size ne, aψne, do the particles repel each other. There is not just one opposite charge particle but aψc till aψne are all opposite charge to aψπ.
If aψc is the complement negative particle, from the post "Sizing Them Up" dated 3 Dec 2014,
aψc (nm) | fc (GHz) | λc(nm) | aψπ(nm) | fπ(GHz) | λπ(nm) | |||
19.34 | 2466067.5 | 121.57 |
|
|
| |||
16.32 | 2922728.6 | 102.57 |
|
|
| |||
15.48 | 3082568.8 | 97.25 |
|
|
| |||
14.77 | 3230699.3 | 92.79 |
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| |||
where the spectra lines are due to basic particles aψc, n=1. And the size of big particles aψπ are given by,
aψπaψc=2.24921
and
2πaψ=λ
It was expected that aψc are negative particles. But the value of 2466067Hz suggests integer reduced micro wave frequency that agitates T+ particles. Based on this, aψ=19.34nm is a T+ particle. What gives?
Simple; an input of energy at reduce resonance frequency (by an integer divisor) imparts energy onto the particle; aψc, a negative temperature particle, grows into aψπ, a positive temperature particle; the matter heats up.
Goodnight...