\(\cfrac { \psi _{ d } }{ m } =2{ c^{ 2 } }cos(\theta )ln(cosh(\cfrac { G }{ \sqrt { 2{ mc^{ 2 } } } } x_z))\)
The ejected \(\psi_n\) is either along the radial line through \(\psi_d\) and the center of the \(\psi\) cloud or in the tangential direction perpendicular to the radial line. Which direction, depends on the sign of the expression for \(v^2_{max}\),
\(v^{ 2 }_{ { max } }=\cfrac { 1 }{ m } \cfrac { \psi _{ n } }{ \psi _{ max } }\left\{ \psi _{ n }-\psi _{ max } \right\} e^{ \psi _{ max } }\left( { e^{ 2\psi _{ max } }-1 } \right) ^{ 1/2 }\)
If the \(LHS\) is negative then the ejected particle leaves tangentially. When the expression is positive the ejected particle leaves along the radial line. In all cases, the ejected particle leaves at \(v_{max}\).
In either case, the quarter charge ejected in turn collides with the next \(\psi\) cloud at \(v_{max}\), ad infinium, otherwise known as a chain reaction.
If the \(\psi\) cloud is unstable, then upon each collision, nuclear fission. In photoelectric emissions, such basic charges eventually leave the confine of the metal and is detect as an electric charge.
All three types of particles, charge, temperature and gravity are subjected to this effect. From which we infer that there are the equivalence of a charge photon, temperature photon and gravity photon, ejecting a basic temperature particle and a basic gravity particle respectively when they collide with a \(\psi\) cloud at \(v_{max}\).
Have a nice day.
