Saturday, November 29, 2014

Why Charges Have Mass?

The force \(F_\rho\) to affect a change in \(\psi\) is given by,

\(F_\rho=-\cfrac{\partial\,\psi}{\partial\,x}\)

This force act against the system and results in work done that is equal to a change in energy \(\psi\).  So, the resistance exerted by the system of a solitary particle on an external agent is given by,

\(F_i=-F_\rho=\cfrac{\partial\,\psi}{\partial\,x}\)

where \(F_i\) is the force exerted by the particle on an external agent.  So,

\(F_i=-F_{\rho}=-i\sqrt { 2{ mc^{ 2 } } }\,G.tanh\left( \cfrac { G }{ \sqrt { 2{ mc^{ 2 } } }  } (x-x_z) \right)\)

The following diagram shows the interaction between two monopoles of positive \(F_i\), ie (-\(F_\rho\))


The concentration of \(\psi\) between the two particles pushes them apart.  And their interaction is thus repulsive.

In a similar way, the diagram below shows the interaction between two monopoles of \(-F_i\), ie (+\(F_\rho\))


The depletion of \(\psi\) between the two particles pulls them together.  And their interaction is thus attractive.

Both diagrams show \(F_{\rho}\), the force developed in previous posts, from an external agent affecting a change in \(\psi\) around the particle.  Strictly speaking the force due to the particles are,


And the interaction of two dissimilar particles is,


If the interaction of two positive \(F_i\) is that of charges (repulsive, like charges repel) and the interaction of two \(-F_i\) is that of gravity particle (attractive, two masses attract), then the interaction of \(F_i\) and \(-F_i\) shown above, is attractive as though the charge has mass; the interaction between two masses is attractive.

If the interaction of \(+F_i\) is that of negative charges, then along the negative \(t_c\) time dimension we have positive charges.  Similarly, along \(-t_g\) time dimension, anti-mass particles.

Negative and positive charges are matter/anti-matter pair, and mass and anti-mass are similarly matter/anti-matter pair.