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Thursday, November 20, 2014

My Own Wave Equation

From the post "Not A Wave But Work Done!",

¨x(2i˙xc)ψtc=ic(1+i˙xc)˙x22ψx2+2¨xVtc --- (*)

derived under the assumption that x=0, a time invariant field.

Multiply (*) by i,

 i¨x(2i˙xc)ψtc=c(1+i˙xc)˙x22ψx2+2i¨xVtc

Multiply by (1i˙xc),

i¨x(2i˙xc)(1i˙xc)ψtc=c(1˙x2c2)˙x22ψx2+2i(1i˙xc)¨xVtc

c(1˙x2c2)˙x22ψx2=i¨x(2˙x2c23i˙xc)ψtc+2(˙xc+i)¨xVtc

c(1˙x2c2)˙x22ψx2=¨x{3˙xc+i(2˙x2c2)}ψtc+2(˙xc+i)¨xVtc

Equating Real terms,

c(1˙x2c2)˙x22ψx2=3˙xc¨xψtc+2˙xc¨xVtc

c(1˙x2c2)˙x2ψx2=¨xc{3ψtc+2Vtc}

Let's define

1γ2=(1˙x2c2)

We have,

c2γ2˙x2ψx2=¨x{3ψtc+2Vtc} --- (**)

Equating Imaginary terms,

¨x(2˙x2c2)ψtc+2¨xVtc=0

¨x0

(2˙x2c2)ψtc=2Vtc

ψtc+(1˙x2c2)ψtc=2Vtc

(1+1γ2)ψtc=2Vtc --- (***)

Substitute the above into (**),

c2γ2˙x2ψx2=¨x{3ψtc(1+1γ2)ψtc}

c2γ2˙x2ψx2=¨x{21γ2}ψtc --- (1)

¨xψtc=c2{2γ21}˙x2ψx2

Equivalently from (1),

(1+˙x2c2)¨xψtc=c2(1˙x2c2)˙x2ψx2

This suggests that when ˙x=c, 1γ2=0

2¨xψtc=0

Then either,

 ¨x=0 and ψtc=Vtc

or,

ψtc=0,

that the total energy of the system is a constant in time tc and is at an extrema.  In this case ψ has a stable point when ˙x=c.  From (***),

ψtc=2Vtc=0

when ˙x=c, and

2ψt2c=22Vt2c

ψ is minimum when V is at its local maximum.  This shows that the system, as far as ψ, the total energy is concerned, can be stable at light speed, ˙x=c.  At that point V is at its local maximum.

We now consider the case when ˙x<<c,

¨xψtc=c2˙x2ψx2

m¨xψtc=c2m˙x2ψx2

With F=m¨x  and p=m˙x,

Fψtc=c2p2ψx2

Since, ψx=F=m¨x

ψxψtc=c2p2ψx2

with tc=12t.eiπ/4,

ψxψt=c2p2.2ψx2.eiπ/4

in time t.

There should be more implications from this equation to prove its validity or disprove it.