F=2mc2xeiπ/2
So,
ψ=−∫2mc2xeiπ/2dx
ψ=−2mc2ln(x)eiπ/2
Similarly ψ is delimited at x=xa, where ψ=0. However, without A (cf. post "Not Exponential, But Hyperbolic And Positive Gravity!"), Coulomb's Law applies for all x>0.
F=mc26πx2eiπ/2
Nice to know there's something old to fall back on.