Friday, November 28, 2014

Beam Me Up Scotty!

If there is no constrain on \(x_z\) other than,

\(m_{\rho}c^2-\int^{x_a}_{0}{\psi}dx\ge0\)

since,

\(x_a=2x_z\)

\(m_{\rho}c^2-\int^{2x_z}_{0}{\psi}dx\ge0\)

from the post "We Still Have A Problem", then \(x_z\) can take on all values from

\(0\lt x_z\lt x_{z\,max}\)

where,

\(m_{\rho}c^2=\int^{2x_{z\,max}}_{0}{\psi}dx\)

A particle under no force from its surroundings will tend towards maximum \(\psi\), being mass-less.  Under the action of a force (or to provide a centripetal force) the particle will change its \(\psi\) such that,

\(F=-\cfrac{\partial\,\psi}{\partial\,x}=F_{external}\)

the force \(F\) as a result of \(\psi\) equals the external force as required.

The particle's mass changes as the forces around it.  In the case of a photon oscillating between one time dimension and one space dimension, it experiences less constrain by way of the space dimension than a charge or gravity particle that oscillate between two space dimensions.  So, a photon fully manifest itself as \(\psi\).  A charge or gravity particle experiences more constrain in two dimensions cannot manifest fully as \(\psi\) and so has mass.

If this is true, we can distill a photon to have mass by applying a force in the one space dimension that it is oscillating.  And since a photon can display negative \(\psi\) effects, an electron (charge) or gravity particle can be made mass-less in a stream of photons, where the particle fully manifest itself as \(\psi\).

Under the right conditions we can all turn into pure energy.