Coriolis Force And My Left Foot

From the previous post "How Time Flies",

$e^{ i\omega t }=\cfrac { \lambda_t }{ 2\pi c } \cfrac { \partial \psi  }{ \partial \, t_{ c } }$

$e^{i\omega t_c}=\cfrac{1}{\sqrt{2}}e^{i(\omega t-\pi/4)}$

and

$e^{i\omega t_g}=\cfrac{1}{\sqrt{2}}e^{i(\omega t+\pi/4)}$

where

$\cfrac{1}{\sqrt{2}}|t|=|t_c|=|t_g|$

The immediate implication is that we can manipulate time, $e^{ i\omega t }$ by manipulating,

 $\cfrac { \partial \psi  }{ \partial \, t_{ c } }={\sqrt{2}}\cfrac { \partial \psi  }{ \partial \, t }$

This is consistent with the ideal of $i\beta$ from the post "Eye Beta Peta".

The second important point is that we can formulate,

$e^{ i\omega t_{ c } }=\cfrac { 1 }{ \sqrt { 2 }  } \left\{ \cfrac { \lambda _{ t } }{ 2\pi c } \cfrac { \partial \psi  }{ \partial \, t_{ c } }  \right\} e^{ -i\pi /4 }$

$e^{i\omega t_g}=\cfrac{1}{\sqrt{2}}\left\{\cfrac { \lambda_t }{ 2\pi c } \cfrac { \partial \psi  }{ \partial \, t_{ c } }\right\}e^{i\pi/4}=\cfrac{1}{\sqrt{2}}\left\{\cfrac { \lambda_t }{ 2\pi c } \cfrac { \partial \psi  }{ \partial \, t_{ g } }\right\}e^{i\pi/4}$  --- (*)

We derived $\psi$ based on charge phenomenon along $t$ from the relationship between $B$ and $E$.  $e^{ i\omega t_{ c } }$ and $e^{i\omega t_g}$ are symmetrical about $e^{ i\omega t }$. $t_g$ can be interchanged with $t_c$.  Equation (*) suggest that there is an analogous force per unit inertia that is perpendicular to gravity, $g$ where

$E=\cfrac{F_c}{q}\equiv \cfrac{F_g}{m}=g$

$F_c$ is the electrostatic force due to the presence of charges and $F_g$, weight due to gravity with mass, $m$.

So,

$\cfrac { \partial B }{ \partial \, t } =-i\cfrac { \partial \, E }{ \partial x^{ ' } }$ suggests,

 $\cfrac { \partial g_B }{ \partial \, t } =-i\cfrac { \partial \, g }{ \partial x^{ ' } }$

where  $g_B$ is a perpendicular gravitational field that exerts a perpendicular force when a body travels in a direction perpendicular to a gravitational field.  The direction of this force, $F_{g_B}$ is given by the right hand rule as if the mass is a negative charge (an electron).  In a totally analogous manner,

$F_{g_B}=\pi v\times g_B$ per unit mass --- (*)

(cf. post "Lorentz Without q", $F_{gB}\equiv F_L$, $F_L$ the Lorentz's Force )  The force, $F_{gB}$ is perpendicular to both $v$ and  $g_B$.

This needs to verified experimentally.  The closest description of such a force is the Coriolis Force; in expression (*) we see the velocity*acceleration term that is associated with the Coriolis Force.

Also, this analogy suggests the existence of a gravitational particle that provides

$g_B =-i\cfrac { \partial \, g }{ \partial x^{ ' } }$

Higgs' particle my left foot, more like time travel disruption.