\(F=i\sqrt { 2{ mc^{ 2 } } }\,G.tanh\left( \cfrac { G }{ \sqrt { 2{ mc^{ 2 } } } } (x-x_z) \right)\)
when \(x_z\) is large, a plateau value for \(-F\) emerged as illustrated below.
The absurd point is that as \(x\rightarrow\infty\), \(g=constant\). If \(-F\) is shifted upwards by \(g_o\) such that,
\(F=i\sqrt { 2{ mc^{ 2 } } }\,G.tanh\left( \cfrac { G }{ \sqrt { 2{ mc^{ 2 } } } } (x-x_z) \right)+g_o\)
where,
\(g_o=i\sqrt { 2{ mc^{ 2 } } }\,G.tanh\left( \cfrac { G }{ \sqrt { 2{ mc^{ 2 } } } } (-x_z) \right)\)
\(g_o=-i\sqrt { 2{ mc^{ 2 } } }\,G.tanh\left( \cfrac { G }{ \sqrt { 2{ mc^{ 2 } } } } x_z \right)\)
and \(F\rightarrow 0\) as \(x\rightarrow\infty\).
But what would be the rationale to do so??
However, this absurdity does provide a constant force that propels the mass particle to light speed, \(\dot{x}=c\), which was one of the possible scenario considered previously.
