High Temperature Requires Thick Skin, Very Thick Skin

From the post "Lucy",

$\tau_o=\cfrac{c^4}{4\pi G}$=299792458^4/(4*pi*6.67384e-11)=9.632e42 N^-1·T².m^-2

where  $G$  is Newton's Gravitational Constant and the unit T is temperature measurement in energy units, which can be converted to J (Joules) or eV.

The value for  $\tau_o$  is very high which makes  $F_T$,  the associated thermal repulsive force very small.

If we consider,

$\cfrac{q^2}{\varepsilon_o}=\cfrac{T_eT_n}{\tau_o}$

at  $T_c$ from the post "Critical Matter/Anti-Matter Fusion Temperature, $T_c$".  We can approximate  $T_c$ using,

$T\propto m$

$\cfrac{T_n}{T_e}=\cfrac{m_p}{m_e}$

$T_e=\cfrac{m_e}{m_p}T_n$

$T_c=T_n+T_e=T_n(1+\cfrac{m_e}{m_p})$

$T_{ e }T_{ n }=\cfrac { m_{ e } }{ m_{ p } } T^{ 2 }_{ n }=\cfrac { m_{ e } }{ m_{ p } } (\cfrac { 1 }{ 1+\cfrac { m_{ e } }{ m_{ p } }  } )^{ 2 }T^{ 2 }_{ c }=\cfrac { m_{ e }m_{ p } }{ (m_{ e }+m_{ p })^{ 2 } } T^{ 2 }_{ c }$

then,

$T^{ 2 }_{ c }=\cfrac { (m_{ e }+m_{ p })^{ 2 } }{ m_{ e }m_{ p } } \cfrac { q^{ 2 } }{ \varepsilon _{ o } } { \tau _{ o } }$

For one hydrogen atom,

$T_c$ = (( 9.10938e-31+1.67262e-27)^2/( 9.10938e-31*1.67262e-27)*(1.602176565e-19)^2/8.8541878176e-12*9.632e42)^(1/2)=7.164e9 T or J, Joules

$T_c\approx$4.472e28 eV

This value is very high.

And hydrogen is indestructible.  It could be that the expression for  $\tau_o$  has been over estimated.