Cont'd from the post "Stable Eight" dated 08 Jul 2016...
In fact all distances \(\Delta a\) that results in a \(\pi\) phase shift, ie.
\(\Delta a=m.2\pi a_{\psi}\)
where \(m=1,3,5..\) is odd, will also result in field confinement.
Given \(n\), the number of complete wavelength(s) along \(2\pi a_{\psi}\) the perimeter of \(\psi\), if \(n\ne\cfrac{1}{2}\), but \(n=1\) minimum we have,
\(2\pi a_{\psi}=\lambda_{\psi}\)
then
\(\pi a_{\psi}=\cfrac{1}{2}\lambda_{\psi}\)
However, if the minimum is \(n=2\),
\(\cfrac{\pi}{2} a_{\psi}=\cfrac{1}{2}\lambda_{\psi}\)
which is impossible given \(m=1\) as,
\(\cfrac{\pi}{2} a_{\psi}\lt 2a_{\psi}\)
as the minimum distance for \(\Delta a\) is \(2a_{\psi}\) in order for \(\psi\) of the particles not to touch.
Since, stable nuclei of eight exist, \(n\le 1\) for \(m=1\); at least for the particles in the stable group of eight. \(m\) on the other hand can be large.
Which points to disassociating/reducing a confined field by increasing the frequency of the particles in the stable group.
When \(m\) is large, \(n\) can be large, increasing the frequency of \(\psi\) will visibly shrink the nuclei and the body as a whole.
Is this how UFOs do their disappearance act? "UFO Over Vasquez Rocks " https://www.youtube.com/watch?v=h0TpWceUZnQ
Good night.
