From the post "Energy Accounting With Fourier" dated 08 Jul 2016, extra energy is needed for BB in circular motion. The extra energy needed reduces the total power in BB. When BB returns from the time dimension, where is this energy when a radiating wire is not in a circular loop (EE not circular).
Is the power 14Ptotal14Ptotal the radiated power?
Yes! (but no, read further...) Because in a circular loop wire antenna, the gap in the loop at the connections is radiating power. This gap is the part of the wire loop that deviates from a circle. When BB is transformed back to EE, EE is supposedly circular, a complex sinusoidal, A(cos(i2πft)+isin(i2πft))A(cos(i2πft)+isin(i2πft)) because BB is a complex sinusoidal. That part of EE that encounters a break in the loop is radiated into space.
When the antenna is a straight wire, one of the components, (Ecos(i2πftEcos(i2πft or Esin(i2πft)Esin(i2πft)) of the circular EE is radiated. The actual power fraction is Pf=12(12)2=18Pf=12(12)2=18.
And no! The initial power fraction of Pf=14Pf=14 is loss bending the EE into a circular wave. This part of the power is not recovered as long as EE remains circular.
In the case of the gap in a circular loop,
Pstr=(θant2π)2Pstr=(θant2π)2 a guess
where θantθant is the angle subtended by the gap at the center of the loop. The power fraction PfPf that applies to a straight wire antenna does not appear here because the applied EE is already circular. No energy is needed to made BB circular.