From the previous post "Increasing Light Speed" dated 10 Jul 2016,
\(c_{measured}=c_{ave}=\cfrac{2}{\pi}c_{max}+c_o\)
The first question is: Why would \(EB\) be dipping in and out of light speed \(c_o\)? The second question is: What is \(c_{max}\)? From the post "Just When You Think c Is The Last Constant" dated 26 Jun 2016, we have,
when we use \(\cfrac{77}{2}=38.5\)
\(c=\sqrt { \cfrac { 38.5*(32\pi ^{ 4 }-1) }{ 64*3.135009*\pi .ln(cosh(3.135009))tanh(3.135009) } *\left( \cfrac {3.135009}{ 0.7369 } \right) ^{ 3 }}\)
\(c_{38.5}=77.5871223\)
when \(\left\lceil\cfrac{77}{2}\right\rceil=38\)
\(c=\sqrt { \cfrac { 38*(32\pi ^{ 4 }-1) }{ 64*3.135009*\pi .ln(cosh(3.135009))tanh(3.135009) } *\left( \cfrac {3.135009}{ 0.7369 } \right) ^{ 3 }} \)
\(c_{38}=77.0816633\)
both without the adjustment to \(c_{adj}\).
If \(c_{max}=c_{38.5}-c_{38}=0.505458945\)
and,
\(c_o=\cfrac{c_{38}+c_{38.5}}{2}\)
this assumes that \(B\) is symmetrical about \(c_o\) and that its value increases in the same way as it decrease; \(B\) is odd about point \((0,c_o)\) and is mirrored about \(x=\pi/2\) in the graph in "Increasing Light Speed" dated 10 Jul 2016. Then,
\(c_{measured}=c_{ave}=\cfrac{2}{\pi}(c_{38.5}-c_{38})+\cfrac{c_{38}+c_{38.5}}{2}\)
\(c_{ave}=\cfrac{2}{\pi}*0.505458945+77.0816633=77.656177\)
and when we adjust for this value,
\(c_adj=c_{ave}.\cfrac { 2ln(cosh(3.135009)) }{ 4\pi\times10^{-7} }\)
\(c_{adj}=302032247\)
This is not closer to the defined value of \(c=299792458\) than the adjusted values of \(c_{38}\) at \(299797757\). But it does suggest a mechanism by which \(EB\) acquire velocity above light speed and present itself as \(B\), by spinning.
The factor \(S_n=\cfrac{77}{2}=38.5\) as the average of \(77\) basic particles on one side of the big particle is applicable only when the particle is in spin. When not in spin but under a repulsive field that pushes the big particle away, the effective number of basic particle facing the repulsive force is \(S_n=\left\lceil\cfrac{77}{2}\right\rceil=38\), as the particle turns away from the repulsive force as it is propelled forward.
Why would \(EB\) drop speed after attaining a maximum speed? Why would \(EB\) return from the time dimension? If \(EB\) returns to the space dimension because it attained the equivalent light speed in the time dimension, the field that propels the particle must act both in the space and time dimension simultaneously. That would make space and time the same dimension not orthogonal.
\(B\) may not be the force in time we are looking for. Don't spin around to time travel yet.
