Big Mushroom

And if you turn a "CHL Bood" given by,

$x=-\cfrac{|F_{drag}|}{n.m_b\omega^2}sin(\cfrac{\pi}{2}-s)*cos(s)$

and

$y=\cfrac{|F_{drag}|}{n.m_b\omega^2}sin(\cfrac{\pi}{2}-s)$

upwards, we have a mushroom cloud,

The blast drove $T^{-}$, negative temperature particles to terminal speed, the drag force they experience sheds the the big particles into smaller groups of $n$ basic particles and send them off to a trajectory defined  by the parametric equations above.  The negative temperature particles are driven off first in a blast, because of their lighter inertia.  They cause moisture in the atmosphere to condense into clouds.  The positive temperature particles that follow infuse into the clouds and create a mix of heat and steam.

The top widest canopy is likely to correspond to $n=1$.

A small "bood" for man, a big KaBoom for mankind.

Note: It is possible to disregard the direction of $x$ and flip $x$ around,

$x=\cfrac{|F_{drag}|}{n.m_b\omega^2}sin(\cfrac{\pi}{2}-s)*cos(s)$

$y=\cfrac{|F_{drag}|}{n.m_b\omega^2}sin(\cfrac{\pi}{2}-s)$

$x=y*cos(s)$

Since,

$sin(\cfrac{\pi}{2}-s)=cos(s)=\cfrac{y}{\cfrac{|F_{drag}|}{n.m_b\omega^2}}$

$\cfrac{|F_{drag}|}{n.m_b\omega^2}x=y^2$

$y=\sqrt{\cfrac{|F_{drag}|}{n.m_b\omega^2}}\sqrt{x}$

in this case the quadratic is parameterized by $\cfrac{1}{\sqrt{n}}$.

A profile is different from an equation.  In a profile the direction of the slope of the shape presented with reference to $y=0$ or $x=0$ is important.  An equation shows the relationship between the variables involved.