This might explain the relative stability of certain nuclei and elements.
With this in mind, consider,
\(f\lambda_{\psi}=c\)
\(2\pi a_{\psi}=\cfrac{1}{2}\lambda_{\psi}\)
\(\small{n=\cfrac{1}{2}}\). \(\psi\) is a half wave that spends half its time in the time dimension and half its time in the space dimension from the posts "Not All Integer But Half Has A Place" dated 12 Dec 2014 and "Half A Wave Really? Exicting! Illuminated!" dated 12 Dec 2014.
For a \(\pi\) phase difference or a length of \(\small{\cfrac{1}{2}\lambda}\) such that the fields from two particles cancel, the two particles will have to be \(\Delta a\) apart,
\(\Delta a = 2\pi a_{\psi}\)
center to center. In this arrangement, the resultant field cancels along the line joining the two particles, beyond the two particles. Their resultant field is concentrated in a plain perpendicular to and bisecting the line joining the two centers of the particles.
Two such pair of particles, where their field planes intersect and are \(\Delta a\) apart line to line. The resultant fields are then restricted to between the parallel lines that bisect the lines joining the particle pair center to center.
Then, when we have another group of four particles where their resultant fields are similarly restricted, and aligned where their field strips overlap at \(\Delta a\) apart, the field strips cancels beyond the two groups. The resultant field is essentially within the square between the two groups of four particles.
When the field is so confined, the particles as a group of eight does not interact with particles outside of its field. They are relatively stable.
Inert elements are stable; eight big particles orbiting as such a group in a nuclei are stable.
Group of two and four are also relatively stable given their restricted fields.
Yet it is a sad day to have reach this far...
