No Sustained "Bood"

From the post "Just When You Think c Is The Last Constant" dated 26 Jun 2016, we have,

$c=\sqrt { \cfrac { S_{ n }(32\pi ^{ 4 }-1) }{ 64\pi .\theta _{ \psi  }ln(cosh(\theta _{ \psi  }))tanh(\theta _{ \psi  }) } *\left( \cfrac { \theta _{ \psi  } }{ 0.7369 }  \right) ^{ 3 } }$

when we replace $\cfrac{77}{2}=S_n$.

When $S_n$ is variable,

$v=\sqrt { \cfrac { S_{ n }(32\pi ^{ 4 }-1) }{ 64\pi .\theta _{ \psi  }ln(cosh(\theta _{ \psi  }))tanh(\theta _{ \psi  }) } *\left( \cfrac { \theta _{ \psi  } }{ 0.7369 }  \right) ^{ 3 } }$ --- (1)

and

$S_n=39-\cfrac{0.5S}{\omega_o}v$ --- (2)

where $S$ is a constant.  From the post "An Egg With Bood..." dated 12 Jul 2016,

$\omega^2=\cfrac{F_{drag}}{\delta m}\cfrac{sin(\theta)}{r}$

at the front tip of the particle, $r\rightarrow 0$ and $\theta\rightarrow 0$.  If we assume

$\lim\limits_{r,\,\theta\rightarrow 0}{\cfrac{sin(\theta)}{r}}=1$

at the tip of the particle,

$\omega^2_t=\cfrac{F_{drag}}{\delta m}$

Since, $F_{drag}\propto v^2$

$\omega^2_t=T_t.v^2$ --- (3)

where $T_t$ is a constant.  The particle spin, $\omega_t$ decreases with decreasing $v$.

When $v$ increases under the action of an attractive field $F.c$, $S_n$ according to expression (2) decreases, which through expression (1) decreases $v$.  As $v$ decreases $\omega_t$ decreases via (3).  But under the action of the field, $v$ increases again.  It seems that the cycle repeats but this is not a sustained oscillation.  Energy in the spin of the particle is not being exchanged for translational kinetic energy in $v$ and vice versa.  $S_n$ presents a lower values because the face that presents a higher number of basic particles towards the attractive field, is being turn away by spin.  As the particle spins, $S_n$ represents the average number of basic particles on one side of the big particle for which they constitute.

This is just a short burst of EB, before $\omega_t$ settles to a constant value.

Substitute (3) into (1)

$\omega _{ t }=\sqrt { \cfrac { S_{ n }T_{t}(32\pi ^{ 4 }-1) }{ 64\pi .\theta _{ \psi  }ln(cosh(\theta _{ \psi  }))tanh(\theta _{ \psi  }) } *\left( \cfrac { \theta _{ \psi  } }{ 0.7369 }  \right) ^{ 3 } }$

given $T_t$ which is a constant, $\omega_t$ is determined.  The particle can spin with constant $\omega_t$ and travel at a speed lower than $c_{39}$.

All that is presented here is under the assumption that $c$, light speed is a constant.