As T increases, rc decreases, since the B field generated by the spinning electron increases.
B=μo4πqv׈rr2c
Why should this decrease electric conductivity? The Lorentz force that acts on passing charges due to this B field is perpendicular to both the B field and the velocity of the charge. A high B field sends the charge clashing into the structure lattice and reduces its drift velocity.
For high conductivity, B field should be minimum but non zero. For a given material, this occurs when,
rc=mec22AT√ATq2π(mec2)2εo−1
is a maximum, ie
drcdT=0
or
q24πTεomec21√ATq2π(mec2)2εo−1−mec22AT2√ATq2π(mec2)2εo−1=0
q24πεomec2=mec22AT(ATq2π(mec2)2εo−1)
q24πεomec2=q22πεomec2−mec22AT
mec22AT=q24πεomec2
T=Aq22πεo(mec2)2
where
A=τo2qvT{r2T+r2or}3/2.ror
A particular temperature exists for which the material is most conductive. Beyond the maximum value, rc decreases monotonously, B increases monotonously, drift velocity decreases and conductivity decreases. As temperature decreases, the complex roots changes to real roots. What was a conductor can change rapidly into a semiconductor after attaining maximum conductivity with decreasing temperature.
And superconductors are all stuck at minimum B, at a specific temperature.
Good night.