\(OH\) not being a charged radical but has a unpaired orbit as part of \(O\) is very interesting.
A lot of \(OH\) will give,
\(OH+OH\rightarrow H_2O_2\)
where the unpaired orbits from two \(OH\)s pair up to give hydroperoxide.
The present of an unpaired orbit makes it ready to react with organic radicals by forming covalent bonds.
\(OH\) is totally innocent in the organic world. \(OH\) is a radical in the organic world because of its unpaired orbit.
By a similar reasoning,
\(CH_3^{+}\)
does not exist, but
\(CH_3\)
with an unpaired orbit as part of \(C\), does exist.
