Cocked eyed with a mole on the left....
What can happen with this odd couple? They must fall in love and bond.
And someone gives someone a free ring,
Neither \(~H\) nor \(OH\) are charged. Since all elements, with an unpaired orbit, of the ionic bond are just as likely to receive the hydrogen, we have in solution,
\(NaH\)
and
\(ClH\)
and
\(2OH\)
all neutral stable compounds, although all polar due to concentration of charges on the smaller hydrogen orbit.
Depending on the readiness of \(ClH\) and \(NaH\) to give away \(H\), the solution may be PH neutral. Since \(OH\) is unbonded, an ionic solution tends to be alkaline. And the displacement of an element with another in a column of the periodic table in an aqueous solution, is with reference to the elements' affinity for \(H\).
\(2IH+Cl_2\rightarrow I_2+2HCl\)
from a solution of \(NaI\) through which \(Cl_2\) gas is passed,
\(2NaI+Cl_2\rightarrow I_2+2NaCl\)
in an aqueous solution. This way \(HCl\) is also produced because, first we have
\(NaI+2H_2O\rightarrow IH+NaH+2OH\)
all uncharged, and then,
\(2IH+Cl_2\rightarrow I_2+2HCl\)
If this is true, that \(OH^{-}\) and \(H^{+}\) are conceptual and do not exist in an aqueous solution, what then happens at the electrodes during electrolysis?
Still how does water break up the sharing of the exposed electrons between two paired orbits?
