A Big Temperature Particle

From the post "A $\Psi$ Gun" dated 31 May 2016,

$f_{res}=0.061\cfrac { c }{ a_{\psi} }$

If the Sun is one big temperature particle,

$a_{\psi}=695700000$

$f_{res}=0.061*299792458/695700000=0.026286$

which is a period of $1/0.026286=38.043s$

What happen to the Sun every 38.0 seconds?

Given,

$G=\cfrac{\pi \sqrt { 2{ mc^{ 2 } } }  }{a_{\psi}}$

$m_{sun}=1.989e30$

$G=\cfrac{\pi \sqrt { 2* 1.989e30*299792458^{ 2 }  }  }{695700000}$

$G=2.7001e15$

None of the $G$ values matches up.  If $m$ is to be mass density,

$G_v=\cfrac{\sqrt{3}G}{\sqrt{4\pi a^3_{\psi}}}$

$G_v=7.1895e1$

and we apply a similar CORRECTION to the previous values;

for the case of an electron,

$G_v=4.511e8*\cfrac{\sqrt{3}}{\sqrt{4\pi* (2.8179403267e−15)^3}}$

$G_v=1.474e30$

and Earth,

$G_v=5.109e14*\cfrac{\sqrt{3}}{\sqrt{4\pi*(6371e3)^3}}$

$G_v=1.552e4$

The values still do not match up.  $m$ is the mass of a point particle.

$m=\cfrac{\Delta M}{\Delta V}=\cfrac{dM}{dV}$  as $\Delta V\rightarrow 0$

the condition $\Delta V\rightarrow 0$ applies for the fact that $m$ is a point.

When the mass is not a point mass, $m$ is the total mass of the particle because the force involved acts on the total mass of the particle.