From the post "A \(\Psi\) Gun" dated 31 May 2016,
\(f_{res}=0.061\cfrac { c }{ a_{\psi} }\)
If the Sun is one big temperature particle,
\(a_{\psi}=695700000\)
\(f_{res}=0.061*299792458/695700000=0.026286\)
which is a period of \(1/0.026286=38.043s\)
What happen to the Sun every 38.0 seconds?
Given,
\(G=\cfrac{\pi \sqrt { 2{ mc^{ 2 } } } }{a_{\psi}}\)
\(m_{sun}=1.989e30\)
\(G=\cfrac{\pi \sqrt { 2* 1.989e30*299792458^{ 2 } } }{695700000}\)
\(G=2.7001e15\)
None of the \(G\) values matches up. If \(m\) is to be mass density,
\(G_v=\cfrac{\sqrt{3}G}{\sqrt{4\pi a^3_{\psi}}}\)
\(G_v=7.1895e1\)
and we apply a similar CORRECTION to the previous values;
for the case of an electron,
\(G_v=4.511e8*\cfrac{\sqrt{3}}{\sqrt{4\pi* (2.8179403267e−15)^3}}\)
\(G_v=1.474e30\)
and Earth,
\(G_v=5.109e14*\cfrac{\sqrt{3}}{\sqrt{4\pi*(6371e3)^3}}\)
\(G_v=1.552e4\)
The values still do not match up. \(m\) is the mass of a point particle.
\(m=\cfrac{\Delta M}{\Delta V}=\cfrac{dM}{dV}\) as \(\Delta V\rightarrow 0\)
the condition \(\Delta V\rightarrow 0\) applies for the fact that \(m\) is a point.
When the mass is not a point mass, \(m\) is the total mass of the particle because the force involved acts on the total mass of the particle.
