What's make a \(H_2\) and what makes a \(He\)?
Fluorine \(F\) is like a Lithium \(Li\) and Neon \(Ne\) like a Helium \(He\)
And we have \(K\) and \(Ca\),
Once the core of the nucleus becomes bigger, \(n=5\) is a admissible solution and we have the transition metals starting with Scandium. The are 10 electrons in \(n=5\) to accommodate 10 transitional elements across the series.
\(n=6\) has twelve elements? Two \(n=6\) makes 24 elements for the Lanthanides and transitional metals
\(n=7\) has fourteen elements and \(n=5\) has ten elements makes 24 for the Actinides and transitional elements. Although it is still possible that across the same series two \(n=6\) shells are being filled instead.
Although we can accommodate transitional metals and both Lanthanides and Actinides series. The reasoning that orthogonal solutions need not be all included, we have many more possibilities for new elements not included in the periodic table. For example, since \(n=3\) is a solution, we can have a single electron around an Oxygen \(O\) core as shown below, in stead of a third electron in a \(n=4\) shell as shown above.
It is still the element Fluorine, \(F\) but behave like Lithium and is more ready to donate the single electron and form \(F^{+}\) ion. It is still Fluorine? Fluorine with multiple personalities.
Hey, Hey, Hey, an explanation for varied oxidation states! These variations in atomic structures but with the same atomic and mass number shall be called diffotoms; for different at the bottom.
Good night, and thanks for isotopes.
