how to make ice? Maybe the paired orbits split and cross,
Crossing the split paired orbit, allows all protons in the configuration on the same side of the paired orbit around the Oxygen nucleus, to synchronize. This makes all the orbit equivalent. The presence of two anti-phase protons from the two Hydrogen atom bends all the orbits of Oxygen at the center.
There is another way to form water, where \(n=2\) is a valid solution to the quantum system then,
A single paired orbit can enclose a \(He\)~\(C\) nucleus with a \(n=2\) proton shell. The outer single paired orbit unpairs into two and bond each with a hydrogen atom. The \(n=2\) shell and the two bonded orbits extend themselves into the vertices of a tetrahedron.
The hydrogen atom being half as small, occupies only one end of the bonded orbit. This creates an imbalance of charge between the center of the water molecule and the two outer bonded orbits.
Hydrogen bonding is the attraction of the relatively positive bonded orbits to the center of the water molecule. Orbits 1, 2, 3 and 4 as shown above, rearrange themselves into the four vertices of a tetrahedron. What about the \(n=2\) paired orbits of the Oxygen? These orbits are closer to the Oxygen nucleus and does not interfere with the arrangement of the two water molecules bonded by hydrogen bonding. All Oxygen orbits revolves over the nucleus and effect each other.
The last scenario is without the complication of bending orbits, but is admissible only if \(n=2\) shell with its new interpretation forms up first and later interacts with the two Hydrogen bonded orbits of the next layer.
