From the post "How Much Further Still Can Gravity Particles Go?" dated 29 Jun 2015, it was proposed that a nucleus can be made up of hydrogen particles (neutral hydrogen nuclei),
\((e^{-},\,g^{-},\,g^{+})\)
\((e^{-},\,T^{-},\,T^{+})\)
and
\((e^{-},\,p^{+})\)
and that the pairs,
\((g^{-},\,g^{+})\) and \((T^{-},\,T^{+})\) are equivalent to \(p^{+}\) and are called proton pair.
In particular \(g^{+}\) acts like a electron anti-neutrino AND a electron neutrino in some radioactive decays.
In the previous posts "Stable, Unstable, All Mental", "Where's Sneezy?", "Order, Order Please!",etc the role of the negative particles are ignored and the focus is on positive particles in the nucleus of hydrogen. The atomic mass is solely contributed by \(g^{+}\) particles and \(p^{+}\) particles in spin and the nucleus is built up from weak fields due to particle spins.
The latter posts concerns the hydrogen nucleus only, consideration given to the weak fields suggests that the previous posts are too simplistic. In particular, the addition of a proton, \(p^{+}\) to the nucleus also requires the addition of other particles, (\(g^{+}\), \(T^{+}\)) or (\(T^{+}\)), in view of the weak fields. Unless, the nucleus set ends with a \(p^{+}\) particle, for example,
(\(g^+\), \(T^+\), \(p^+\))
then on receiving an extra \(p^{+}\), becomes,
(\(g^+\), \(T^+\), \(2p^+\))
where the weak field due to the spinning \(T^{+}\) particle attracts two \(p^{+}\) particles.
Thus \(\beta\) decays have to reconsidered in this new light.
Note: The post "How Much Further Still Can Gravity Particles Go?" dated 29 Jun 2015 and other posts suggesting that the hydrogen nucleus can be,
\((e^{-},\,g^{-},\,g^{+})\) or
\((e^{-},\,T^{-},\,T^{+})\)
are defunct.
