Stable, Unstable, All Mental

Oh no, these are all stable isotopes,

($T^+$, $p^+$)

($p^+$)

($g^+$, $T^+$, $p^+$)

($T^+$, $p^+$, $g^+$)  and  ($T^+$, $p^+$, $g^+$, $T^+$)

($p^+$, $g^+$)  and  ($p^+$, $g^+$, $T^+$)

($g^+$, $T^+$, $p^+$, $g^+$)  and  ($g^+$, $T^+$, $p^+$, $g^+$, $T^{+}$)

the spins of $p^{+}$ particles do not contribute to the mass of the nuclei, only the presence of $g^{+}$ particle.  In which case, hydrogen isotopes have zero mass, mass of one $g^{+}$ and the mass of two $g^{+}$.  The relative abundance of these stable isotopes give rise to the decimals in hydrogen mass that can not be factored.

The notion of $p^{+}$ having mass $g^{+}$ is the result of having to add the tuple ($g^+$, $T^+$, $p^+$) to any nucleus ending with a $p^{+}$ particle in the cyclic permutation set.  The tuple must contain a $g^{+}$ particle.  Such an array of stable isotopes with different positions of $p^{+}$ in the nucleus may also add to the decimal points in experimental isotope mass measurements, if the weak $g$ field generated by the spinning $p^{+}$ particles also contribute to mass.  What about spins?  Spins seem to be associated with $g^{+}$ particles only.

Unstable nuclei are not any members of the cyclic permutation set.  For example,

($3g^+$, $T^+$, $p^+$)

($T^+$, $p^+$, $3g^+$)  and  ($T^+$, $p^+$, $3g^+$, $T^+$)

($p^+$, $3g^+$)  and  ($p^+$, $3g^+$, $T^+$)

are all Hydrogen-3, $^3H$ with spin $\small{\cfrac{1}{2}}^{+}$; the group $3g^{+}$ spins as one.  What about $^3H$ with $2^{-}$ spin?

What is $g^{+}$ and how can it transmute to a charge?

The time axes, $t_g$ and $t_c$ of a $g^{+}$ particle swapped.  The result is an electron that leaves the nucleus; $\beta^-$ decay.

How does such a swap occurs?  'Til next time...