Consider all the stable isotopes of hydrogen,
(T+, p+)
(p+)
(g+, T+, p+)
(T+, p+, g+) and (T+, p+, g+, T+)
(p+, g+) and (p+, g+, T+)
(g+, T+, p+, g+) and (g+, T+, p+, g+, T+)
If β− decay is still centered around g+ particles then the following scheme maybe possible,
Where a photon, Pp+ collides with a g+ particle. The two time axes, tc and tg of g+ swapped and transmute it to a e− particle which is ejected from the nucleus. The photon slows down and becomes a proton, p+. This proton merged with the lower or higher layer proton, p+ in the nucleus to give 2p+. When the proton merged with a higher particle, the falling particle will emit a small amount of energy. For example,
(g+, T+, p+)→(2p+) + e− + T+
in this case, T+ is the electron anti-neutrino and the captured photons merge with a higher layer proton to give two protons. Furthermore,
(T+, p+, g+)→(T+, 2p+) + e−
without the emission of an electron anti-neutrino. And,
(T+, p+, g+, T+)→(T+, 2p+) + e− + T+
with the emission of an electron anti-neutrino and the photons merged down one layer.
The set (T+, p+, g+) arises from considering positive particles being captured by weak fields due to positive particle spins in the hydrogen nucleus. It is a repeating series that occurs in the nuclei of other elements. If this β− decay scheme is true, it will also apply to all nuclei susceptible to such decays.
The T+ particle originates from the nucleus. It is released as the weak field holding it disappeared when the spinning g+ particle generating the field is transmuted to a e− particle after colliding with a photon.
Note: How does a photon slow down? The time dimension wrap around a space dimension. When the particle has light speed in space, its time speed is zero. It is a photon. When the photon slows down in space, its time speed increases towards light speed. When its speed in space is zero, it becomes a particle, its speed along tT is light speed, c.