Consider all the stable isotopes of hydrogen,
(\(T^+\), \(p^+\))
(\(p^+\))
(\(g^+\), \(T^+\), \(p^+\))
(\(T^+\), \(p^+\), \(g^+\)) and (\(T^+\), \(p^+\), \(g^+\), \(T^+\))
(\(p^+\), \(g^+\)) and (\(p^+\), \(g^+\), \(T^+\))
(\(g^+\), \(T^+\), \(p^+\), \(g^+\)) and (\(g^+\), \(T^+\), \(p^+\), \(g^+\), \(T^{+}\))
If \(\beta^{-}\) decay is still centered around \(g^{+}\) particles then the following scheme maybe possible,
Where a photon, \(P_{p^{+}}\) collides with a \(g^{+}\) particle. The two time axes, \(t_c\) and \(t_g\) of \(g^{+}\) swapped and transmute it to a \(e^{-}\) particle which is ejected from the nucleus. The photon slows down and becomes a proton, \(p^{+}\). This proton merged with the lower or higher layer proton, \(p^{+}\) in the nucleus to give \(2p^{+}\). When the proton merged with a higher particle, the falling particle will emit a small amount of energy. For example,
(\(g^+\), \(T^+\), \(p^+\))\(\rightarrow\)(\(2p^{+}\)) + \(e^{-}\) + \(T^{+}\)
in this case, \(T^{+}\) is the electron anti-neutrino and the captured photons merge with a higher layer proton to give two protons. Furthermore,
(\(T^+\), \(p^+\), \(g^+\))\(\rightarrow\)(\(T^{+}\), \(2p^{+}\)) + \(e^{-}\)
without the emission of an electron anti-neutrino. And,
(\(T^+\), \(p^+\), \(g^+\), \(T^+\))\(\rightarrow\)(\(T^{+}\), \(2p^{+}\)) + \(e^{-}\) + \(T^{+}\)
with the emission of an electron anti-neutrino and the photons merged down one layer.
The set (\(T^+\), \(p^+\), \(g^+\)) arises from considering positive particles being captured by weak fields due to positive particle spins in the hydrogen nucleus. It is a repeating series that occurs in the nuclei of other elements. If this \(\beta^{-}\) decay scheme is true, it will also apply to all nuclei susceptible to such decays.
The \(T^{+}\) particle originates from the nucleus. It is released as the weak field holding it disappeared when the spinning \(g^{+}\) particle generating the field is transmuted to a \(e^{-}\) particle after colliding with a photon.
Note: How does a photon slow down? The time dimension wrap around a space dimension. When the particle has light speed in space, its time speed is zero. It is a photon. When the photon slows down in space, its time speed increases towards light speed. When its speed in space is zero, it becomes a particle, its speed along \(t_T\) is light speed, \(c\).