Only if the photon that drives the particles apart by \(x=\pi\) does not also impart energy onto the orthogonal dimension along which energy are oscillating, by which the particle would be entangled. As such, in order that the split particles be entangled, this photon must firstly, exists in the same time dimension as \(2q\) and secondly has no energy in the oscillating dimension. There can only be one possibility, a photon of the opposite particle. For example, in the case of a big electron,
If the momentum of such a photon is expended in driving the split particles apart, what then happened to the energy in the orthogonal oscillatory dimension? In the above example, where do the energy along \(t_g\) go, after the collision? （This photon, when \(x,\,\, v=c\) is replaced with \(t_T,\,\,v=c\) becomes a proton.)
If energy along \(t_g\) is still oscillating, then it is still a photon but at lower speed. Only part of the energy of the photon has been transfer to the big particle. The photon reduced speed after the collision, and is accelerated to light speed again. Photons are self-propelling. If this energy along \(t_g\) is not oscillating, it is no longer a wave. Can such dissipative, free energy exist?
It is very likely that only the former case applies and that such free energy fragments does not exist, only waves/particles.
