From the post "What Am I Doing? Pressure Lamp",
w2a=2p2(To−1)
In some model, p=ξωo
ω2a=2ξ2ω2oTo−1 --- (1)
since,
ω2o=Toω2a
where T=Toeiwat provides the driving force; re make to oscillate by varying T. To fixes the position the center of oscillation, reo through the graph of re vs T. Since T is sinusoidal, the DC value of T is To/√2,
re(To√2)=rekink
So, given a re vs T profile, To determines reo and is set at the kink of the graph. Substituting for ωo expression (1) becomes,
ω2a=2ξ2Toω2aTo−1
1=2ξ2ToTo−1
ξ2=12(1−1To)
Which would suggest that the system output is totally determined up to this point. The amount of damping in the system can be adjusted by changing To, more accurately the DC value To√2.
But is the oscillator model valid in the first place? Consider, re(T)
dre(T)dt=dre(T)dTdTdt
d2re(T)dt2=ddt(dre(T)dT)dTdt+ddt(dTdt)dre(T)dT
d2re(T)dt2=d2re(T)dT2(dTdt)2+dre(T)dTd2Tdt2
This means is a system re(T), can made to accelerate by varying T and such a "force" is given by the expression above.
And if we consider a characteristic equation for oscillating system of the from,
¨re+2p˙re+ω2ore=0
Applying a driving force as above,
¨re+2p˙re+ω2ore=d2redT2(dTdt)2+dredTd2Tdt2
We know that on the re vs T profile where dredT is high, d2redT2 is close to zero, and the value of dredT is approximately a constant for small Δre. With this simplifications,
¨re+2p˙re+ω2ore≈dredTkinkd2Tdt2
Since T is sinusoidal d2Tdt2 is also sinusoidal and standard solutions apply. w2o−2p2=w2a for a damped system under forced oscillation is valid here. Notice that there cannot be resonance unless the system is damped; when p=0, ωa cannot be equal to ωo unless they are both zero.