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Sunday, September 21, 2014

Where Damping Is Light

From the post "What Am I Doing? Pressure Lamp",

w2a=2p2(To1)

In some model,  p=ξωo

ω2a=2ξ2ω2oTo1 --- (1)

since,

ω2o=Toω2a

where  T=Toeiwat provides the driving force;  re  make to oscillate by varying  T.  To  fixes the position  the center of oscillation,  reo through the graph of  re  vs  T.  Since  T  is sinusoidal, the  DC value of  T  is  To/2,

re(To2)=rekink

So,  given a  re  vs  T profile,  To determines  reo and  is set at the kink of the graph.  Substituting for  ωo expression  (1) becomes,

ω2a=2ξ2Toω2aTo1

1=2ξ2ToTo1

ξ2=12(11To)

Which would suggest that the system output is totally determined up to this point.  The amount of damping in the system can be adjusted by changing  To,  more accurately the DC value  To2.

But is the  oscillator model valid in the first place?  Consider,    re(T)

dre(T)dt=dre(T)dTdTdt

d2re(T)dt2=ddt(dre(T)dT)dTdt+ddt(dTdt)dre(T)dT

d2re(T)dt2=d2re(T)dT2(dTdt)2+dre(T)dTd2Tdt2

This means is  a system  re(T),  can made to accelerate by varying  T and such a "force" is given by the expression above.

And if we consider a characteristic equation for oscillating system of the from,

¨re+2p˙re+ω2ore=0

Applying a driving force as above,

¨re+2p˙re+ω2ore=d2redT2(dTdt)2+dredTd2Tdt2

We know that on the  re  vs  T  profile where  dredT  is high,  d2redT2 is close to zero, and the value of  dredT  is approximately a constant for  small  Δre.  With this simplifications,

¨re+2p˙re+ω2oredredTkinkd2Tdt2

Since  T  is sinusoidal  d2Tdt2  is also sinusoidal and standard solutions apply.  w2o2p2=w2a  for a damped system under forced oscillation is valid here.  Notice that there cannot be resonance unless the system is damped;  when  p=0,  ωa  cannot be equal to  ωo unless they are both zero.