Banana + Mochi = Banana Mochi

From the previous post "If The Universe Is A Mochi...", we would expect the universe to be roughly proportioned into,

Given,

$m_p=\cfrac{m}{2^n}$

$\begin{matrix} \begin{matrix} m_p & 0 \\ 2m_p & 2^{n-2} \\ 4m_p & 2^{n-4}\\8m_p &2^{n-6} \\..&..\\..&..\end{matrix} &  \\  &  \end{matrix}$
The most abundant elements is of the type  $2m_p$.

If we sum all the masses,

$0.m_p+2^{n-2}.2m_p+2^{n-4}.4m_p+2^{n-6}.8m_p+..$

And taking the limit  $n\rightarrow\infty$,

$\lim_{n\rightarrow\infty}\left\{2^{n-1}m_p(1+\cfrac{1}{2}+\cfrac{1}{4}+...)\right\}=\lim_{n\rightarrow\infty}\left\{2^{n}\cfrac{m}{2^n}\right\}=m$

which is the mass the big bang started with.

It is most interesting that this model suggests a binary count of masses in the universe.  That all masses are related to a constant ($m_p$)  by some power of 2,

$m_n=2^nm_p$,

and  $m_p$  itself being rare.